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Given the function ƒ(x) = 3x + 5, find ƒ(4) and x such that ƒ(x) = 38.

Given the function ƒ(x) = 3x + 5, find ƒ(4) and x such that ƒ(x) = 38.
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Given the function ƒ(x) = 3x + 5, find ƒ(4) and x such that ƒ(x) = 38.

User Zhi Lv
by
7.6k points

1 Answer

1 vote

Answer:

just plug 4 inside f(x)=3(4)+5

3x+5=38

3x=33

Divid by 3 on both sides

x=11

Explanation:

User Manish Patiyal
by
8.2k points
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