Answer:
941 K (668°C)
Step-by-step explanation:
We have the following data:
Initial pressure : P1 = 1.45 atm
Initial temperature: T1 = 52°C + 273 = 325 K
Final pressure: P2 = 4.2 atm
Final temperature: T2 = ?
The relation between pressure and temperature for a gas at constant volume is given by Gay-Lussac's law:
P1/T1 = P2/T2
That means that the pressure is directly proportional to the absolute temperature (in K). So, we calculate T2 from the equation:
T2 = P2 x T1/P1 = 4.2 atm x (325 K/1.45 atm) = 941 K
Therefore, the final temperature would be 941 K (668°C). This is consistent with the law, that states that if the pressure increase, the temperature will be increased.