Question

A park has the shape of a trapezoid.

The shortest side of the park and its height have the same dimension.

Write numbers in the boxes to show the missing dimensions. What is the area of the park?

Hint: There are 3 parts in this question
Part 1 you need to find what is A
Part 2 you need to find what is B
Part 3 You need to calculate the area of all the figure ( find the area of the rectangle and two triangles then sum them all up)
Do not forget the unit!!

Answer 1

`the\: answer \: is \: {108 \: mi.}^(2)`

Explanation:

Given hints:

a.) A park has the shape of a trapezoid.

b.) The shortest side of the park and its height have the same dimension.

In the given figure, the shortest side of the park is A. Since it is mentioned that the height and its shortest side have the same dimension, we can therefore say that the measure of A is 9 mi.

The longest side appears to be 6 miles longer that the shortest side:

`b = a + 3 \: mi + 3 \: mi = a + 6 \: mi`

Therefore, B = A + 6 mi. = 9 mi. + 6 mi. = 15 mi.

Let's now determine the area of the park:

`area = (a + b)/(2) h`

Where,

A = 9 mi.

B = 15 mi

H = 9 mi.

`area = (a + b)/(2) h \\ \\ = (9 \: mi. +15 \: mi. )/(2) (9 \: mi.) \\ \\ = (24 \: mi.)/(2)(9 \: mi.) \\ \\ = (12 \: mi.)(9 \: mi. \\ \\ area = {108 \: mi.}^(2)`

The area of the park is 108 mi^2.