Answer:
1240 m/s
Step-by-step explanation:
[Do you mean 0.035 kg bullet?]
Since the momentum of the system is conserved,
Let u m/s be the initial velocity of the bullet
0.035u = 8.6(5+0.035)
u ~= 1237.1714 m/s
u = 1240 m/s (3 sig. fig.)
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