Question

How many moles of Ag are in 43.1 grams of Ag2O






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Answer 1

0.372 mol (corr. to 3 sig. fig.)

Step-by-step explanation:

no. of mole of Ag₂O

= mass of Ag₂O ÷ relative atomic mass of Ag₂O

= 43.1 ÷ ( 107.9 × 2 + 16 )

≈ 0.185936151 mol

∵ Ratio of Ag:Ag₂O = 2:1

∴ no. of mole of Ag

= no. of mole of Ag₂O × 2

≈ 0.371872303 mol

= 0.372 mol (corr. to 3 sig. fig.)