Answer:
The sound intensity that the other student measure, I₂ is expected to be;
A) 6.2 × 10⁻⁸ W/m²
Step-by-step explanation:
The measure of sound intensity is given by the following formula;
![I = (P)/(4 \cdot \pi \cdot R^2)](https://img.qammunity.org/2022/formulas/physics/high-school/ayqpi3z3ffwqiodca94i09b96fheflctin.png)
![(I_2)/(I_1) = (R_1^2)/(R_2^2)](https://img.qammunity.org/2022/formulas/physics/high-school/20nplsgwa0gyjifxnw7rl3xtedxpuvau66.png)
Where;
I = The intensity
R = The radius
P = The power of the sound
Whereby we have;
The distance of the two people talking, R₁ = 3.0 m
The measure of the sound intensity, I₁ = 1.1 × 10⁻⁷ W/m² (from an online source)
The distance of the other student from the two people talking, R₂ = 4.0 m
Therefore, the estimate of the sound intensity, I₂, is given as follows;
![{I_2} = (R_1^2)/(R_2^2) * {I_1}](https://img.qammunity.org/2022/formulas/physics/high-school/qqpchox4kry95xojmpcu0zj7gns2l6ined.png)
![{I_2} = ((3.0 \, m)^2)/((4.0 \, m)^2) * 1.1 * 10^(-7) \ W/m^2 = 6.1875 * 10^(-8) \ W/m^2](https://img.qammunity.org/2022/formulas/physics/high-school/92g4s5w0y52mmewi9witn8gi5sda115s0w.png)
I₂ = 6.1875 × 10⁻⁸ W/m²
∴ The sound intensity that the other student measure, I₂ ≈ 6.2 × 10⁻⁸ W/m²