Question

NO LINKS!!

Solve each problem and show all supporting work. Mark solutions and answers clearly. ​

Answer 1

1. (a) 40; (b) -8; (c) -5
2. -2/((x -1)(x -1 -h))

Explanation:

1)

All of the values in parentheses are less than 6, so you only need the first part of the function definition.

f(x) = x^2 +6x = (x +6)x

f(4) = (4+6)(4) = 40

f(-2) = (-2 +6)(-2) = -8

f(-1) = (-1 +6)(-1) = -5

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2)

`(f(x+h)-f(x))/(h)=((2)/((x+h)-1)-(2)/(x-1))/(h)=2((x-1)-(x+h-1))/(h(x-1)(x+h-1))\\\\=\boxed{(-2)/((x-1)(x-1+h))}`