Question

Determine the force of gravitational attraction between the earth (m = 5.98 x 10^24kg)

and a 70-kg physics student, where the student is at a distance of 6.39 x 10^6 m from earth's
center.

Answer 1

F = 683.8 N

Step-by-step explanation:

The gravitational force of attraction between the Earth and the student is given by Newton's Law of Gravitation as follows:

`F = (Gm_(1)m_(2))/(r^2)`

where,

F = Force = ?

G = Universal gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

m₁ = mass of Earth = 5.98 x 10²⁴ kg

m₂ = mass of student = 70 kg

r = distance between Earth and student = 6.39 x 10⁶ m

Therefore,

`F = ((6.67\ x\ 10^(-11)\ Nm^2/kg^1)(5.98\ x\ 10^(24)\ kg)(70\ kg))/((6.39\ x\ 10^6\ m)^2)\\`

F = 683.8 N