217k views
1 vote
as of a certain date there has been a total of 18072 performances of two show on broadway with 2892 more performances of show A than B how many performances were there of each show

User ZenMaster
by
4.4k points

1 Answer

4 votes
Answer:
A = 10,482
B = 7,590

Step-by-step explanation:

If A is the number of times show A was performed, and B is the number of times show B was performed:

We know that A + B = 18072
And we know A = B + 2892

So we’ll substitute the expression (B + 2892) for A in the first equation and solve for a numerical value of B:

A + B = 18072
B + 2892 + B = 18072
2B + 2892 = 18072
2B = 15,180
B = 7,590

A = B + 2892
A = 7590 + 2892
A = 10,482

Check the math
A + B = 18072
10,482 + 7,590 = 18,072

Let me know if you have questions
User Nitika
by
4.1k points