Question

How many moles of ammonia gas can be formed from 14.0 L of hydrogen gas 300 K and a pressure of 2.0 atm

Answer 1

n = 1.14 mol

Step-by-step explanation:

Hello there!

In this case, according to the ideal gas law:

`PV=nRT`

It is possible to solve for the moles of the gas given the volume, temperature and pressure:

`n=(PV)/(RT)`

Thus, we plug in 14.0 L, 300 K and 2.0 atm to obtain:

`n=(2.0atm*14.0L)/(0.08206(atm*L)/(mol*K)*300K)\\\\n=1.14mol`

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