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If the maximum range of projectile is x. show that the maximum height reached by the same projectile is x/4.



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Step-by-step explanation:

Given that,

The maximum range of a projectile is x.

Maximum range occurs when the angle of projection is 45°. Using formula for maximum range.


R=(v^2)/(g)

According to the question,


x=(v^2)/(g) ...(1)

Maximum height,


h=(v^2)/(2g)

From equation (1).


h=(x)/(2)

Hence, this is the required solution.

User Faustin
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