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If the area of a rectangle is 64cm squared, how many different perimeters are possible when the dimensions are whole numbers

User Paulvs
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1 Answer

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Answer:

2 different perimeters, 32 cm and 40 cm

Explanation:

Given the area of a rectangle is 64 cm squared.

We know, Area of the rectangle is = length x breath

∴ 64 = 8 x 8

Hence the sides can be 8 cm by 8 cm.

So the perimeter of the rectangle is = 8 cm + 8 cm + 8 cm +8 cm

= 32 cm

Also, Area of the rectangle is = length x breath

∴ 64 = 16 x 4

So the perimeter of the rectangle is = 16 cm + 4 cm + 16 cm +4 cm

= 40 cm

User Khanal
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