Answer:
The three quadratic equations are;
x² + 3 = 0
x² + 2·x + 1 = 0
x² + 3·x + 2 = 0
Explanation:
1) A quadratic equation with no real solution is one with an imaginary solution such as one with a negative square root
We can write the quadratic equation as follows;
x² + 3 = 0
∴ x = √(-3) = √(-1) ×√3 = i·√(3)
Therefore, the equation f(x) = x² + 3, has no real root at f(x) = 0
2) A quadratic that has 1 real root is of the form;
(x + 1)² = 0
The root of the equation is x = -1 from (x + 1) = ((-1) + 1)² = 0²
Which gives;
(x + 1)² = (x + 1)·(x + 1) = x² + 2·x + 1 = 0
Therefore, the quadratic (x + 1)² = 0 has only one real root
3) A quadratic that has 2 real root is of the form;
(x + 1)·(x + 2) = 0
x² + x + 2·x + 2 = 0
x² + 3·x + 2 = 0
Therefore, the three quadratic equations are;
x² + 3 = 0
x² + 2·x + 1 = 0
x² + 3·x + 2 = 0