Answer:
Parent 1 = RrBb
Parent 2 = RrBb
Step-by-step explanation:
This question involves two genes in guinea pigs. The allele for rough coat (R) is dominant to smooth coat (r), and the allele for black coat (B) is dominant to white coat (b).
According to this question, two rough black guinea pigs when bred together produced two offsprings. One of the offsprings is rough white (R_bb) and the other is smooth black (rrB_). This means that, to produce such offsprings, the parents must be both heterozygous for both genes (RrBb). Please find the punnet square for this cross attached