Answer:
integer 1 = 8
integer 2 = x+2 = 8+2 = 10
integer 3 = x+4 = 8+4 = 12
Explanation:
integer 1 = x , smallest
integer 2 = y , x+12
integer 3 = z , largest, x+4
three times the smallest is twice the largest.
3 (x) = 2 (x+4)
solve for x:
3x = 2x + 8
3x-2x = 8
x = 8
Replacing:
integer 1 = 8
integer 2 = x+2 = 8+2 = 10
integer 3 = x+4 = 8+4 = 12