Answer:
Subtract
12
from both sides of the equation.
x
2
+
y
2
−
12
x
+
2
y
=
−
12
Complete the square for
x
2
−
12
x
.
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(
x
−
6
)
2
−
36
Substitute
(
x
−
6
)
2
−
36
for
x
2
−
12
x
in the equation
x
2
+
y
2
−
12
x
+
2
y
=
−
12
.
(
x
−
6
)
2
−
36+y2+2y=−12
Move
−36
to the right side of the equation by adding
36
to both sides.
(x−6)2+y2+2y=−12+36
Complete the square for
y2+2y.
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(y+1)2−1
Substitute
(y+1)2−1
for
y2+2y
in the equation
x2+y2−12x+2y=−12.
(x−6)2+(y+1)2−1=−12+36
Move
−1
to the right side of the equation by adding
1
to both sides.
(x−6)2+(y+1)2=−12+36+1
Simplify
−12+36+1.
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(x−6)2+(y+1)2=25
This is the form of a circle. Use this form to determine the center and radius of the circle.
(x−h)2+(y−k)2=r2
Match the values in this circle to those of the standard form. The variable
r
represents the radius of the circle,
h
represents the x-offset from the origin, and
k
represents the y-offset from origin.
r=5 h=6 k=−1
The center of the circle is found at
(h,k).
Center:
(6,−1)
These values represent the important values for graphing and analyzing a circle.
Center: (6,−1)
Radius:
5
image of graph
Explanation: