Use substitution to find the solutions to the systems.

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asked May 4, 2022 152k views

2 Answers

Bullets · Answer 1 · 2022-05-11T12:06:38+0000

Okay you can set them equal to each other...

5.) y = x^2-7x+4; y = x-3
x-3 = x^2-7x+4
x^2-8x+4 = 0
(x-1) (x-7)
x = 1, 7

6.) y = x^2-5x+10; y = 2x^2-6x+4
x^2-5x+10 = 2x^2-6x+4
x^2-x-6 = 0
(x-3)(x+2)
x = 3, -2

Use substitution to find the solutions to the systems.

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