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the diagram shows two rectangles that both have a width of 6 cm. the difference between the perimeters of the two rectangles is 10 cm. calculate the difference between the areas of the two rectangles

User Gsquaredxc
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1 Answer

6 votes

Answer:

Difference in area = 30 cm²

Explanation:

Given:

Width of both rectangle = 6 cm

Difference in perimeter = 10 cm

Find:

Difference in area

Computation:

Perimeter of r1 = 2(L1 + 6)

Perimeter of r2 = 2(L2 + 6)

Difference in perimeter = 10 cm

2(L1 + 6) - 2(L2 + 6) = 10

L1 + 6 - L2 - 6 = 5

L1 - L2 = 5

Difference in area = [L1 x 6] - [L2 x 6]

Difference in area = 6[L1 - L2]

Difference in area = 6[5]

Difference in area = 30 cm²

User Cameron Taggart
by
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