23.8k views
0 votes
Solve for x and y algebraically:
x + y = 8 and 3x + 2y = 21​

2 Answers

6 votes

Answer:

x = 5

y = 3

Step-by-step explanation:

x + y = 8 and 3x + 2y = 21

Here We use Substitution Method

x + y = 8 ...(1)

3x + 2y = 21 ...(2)

From equation (1) we get

x + y = 8

x = 8 - y

Now the value of x = 8 - y in equation (2)

3(8 - y) + 2y = 21

24 - 3y + 2y = 21

- y = 21 - 24

y = 3

Then Put the value of y in equation (1)

x + (3) = 8

x + 3 = 8

x = 8 - 3

x = 5

Thus The value of x is 5 and y is 3

For Verification Only:

x + y = 8

5 + 3 = 8

8 = 8

3x + 2y = 21

3(5) + 2(3) = 21

15 + 6 = 21

21 = 21

L.H.S = R.H.S

-TheUnknownScientist

User Alex Skrypnyk
by
5.0k points
0 votes

Step-by-step explanation:

ans ...(5,3)..............

Solve for x and y algebraically: x + y = 8 and 3x + 2y = 21​-example-1
User Qartal
by
5.3k points