Question

Q7) A box sliding with a velocity of 5 m/s accelerates at 2 m/s^2. How

much is the box displacement after 6 s?

Answer 1

The box displacement after 6 seconds is 66 meters.

Step-by-step explanation:

Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object (
`\Delta s`), in meters, can be determined by the following expression:

`\Delta s = v_(o)\cdot t+(1)/(2)\cdot a\cdot t^(2)` (1)

Where:

`v_(o)` - Initial velocity, in meters per second.

`t` - Time, in seconds.

`a` - Acceleration, in meters per square second.

If we know that
`v_(o) = 5\,(m)/(s)`,
`t = 6\,s` and
`a = 2\,(m)/(s^(2))`, then the box displacement after 6 seconds is:

`\Delta s = 66\,m`

The box displacement after 6 seconds is 66 meters.