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Prove that tan(45+A)tan(45-A)=1
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Prove that tan(45+A)tan(45-A)=1

User Adrien De Peretti
by
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1 Answer

4 votes

L.H.S

= tan(45° + A).tan(45° + A)

= (1 + tanA)/(1 - tanA) . (1 - tanA)/(1 + tanA)

= 1

= R.H.S

Hope it will help :)

User Rzb
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