Question

Fill in the blanks. (With picture) 15 pts

(Simplify your answers. Use integers or fractions for any numbers in the expressions.

Answer 1

Given:

The expression is:

`\left((11)/(19)n-8\right)+\left((1)/(19)n+10\right)=\left(\_\_\_+(1)/(19)n\right)+\left(-8+\_\_\_\right)`

`=\_\_\_n+\_\_\_`

To find:

The missing values.

Solution:

We have,

`\left((11)/(19)n-8\right)+\left((1)/(19)n+10\right)`

It can be written as

`\left((11)/(19)n-8\right)+\left((1)/(19)n+10\right)=\left((11)/(19)n+(1)/(19)n\right)+\left(-8+10\right)`

So, the values for the first two boxes are
`(11)/(19)n` and 10 respectively.

On simplification, we get

`\left((11)/(19)n-8\right)+\left((1)/(19)n+10\right)=\left((11+1)/(19)n\right)+\left(2\right)`

`\left((11)/(19)n-8\right)+\left((1)/(19)n+10\right)=(12)/(19)n+2`

So, the values for third and fourth boxes are
`(12)/(19)` and 2 respectively.