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Which function is equivalent to y=4(x−2)^2+10?

y=4x^2−4x+14

y=4x^2+14

y=4x^2−16x+56

y=4x^2−16x+26

User NJP
by
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2 Answers

0 votes

Answer:

y=4x^2 - 16x +26

Explanation:

step 1 :

evaluate (x-2)^2 = that has the form of ( a- b) ^2

a^2 - 2ab + b^2

so ( x- 2)^2 = x^2- 4x + 4

step 2 :

multiple the 4 to the equation that you just evaluated

4( x^2 - 4x + 4) = 4x^2 - 16x + 16

step 3

take the new equation +10

4x^2 -16x +16 +10

User Gcbirzan
by
4.3k points
2 votes

Answer:

y=4x²- 16x +26

Explanation:

4(x-2)² +10= 4(x²-4x+4) +10=4x²-16x+16 +10

:.y=4x²-16x+26

User Robdll
by
3.8k points