Step-by-step explanation:
a. Write a balanced equation
The balanced equation for the reaction is given as;
Zn + AgNO3 → Ag + ZnNO3
b. Interpret the equation by particles and by moles
In this equation, 1mol of Zn reacts with 1 mol of AgNO3 to from 1 mol of Ag and 1 mol of ZnNO3
1 mol = 6.022 * 10^23 particles
c. What is the limiting reactant?
The mol ratio between both reactants is 1 : 1 from the equation.
Converting the masses given to ml;
Number of mol = Mass / Molar mass
Zn;
Number of mol = 6.70 / 65.38 = 0.1025 mol
AgNO3;
Number of mol = 27.5 / 169.87 = 0.1619 mol
The limiting reactant in this reaction is Zn. This is because Zn would get used up before AgNO3 according to the number of moles calculated.
d. What is the theoretical mass of silver that will be produced?
1 mol of Zn produces 1 mol of Ag
0.1025 mol of Zn would also produce 0.1025 mol mol of Ag
Mass = Molar mass * Number of Moles = 107.87 * 0.1025
Mass = 11.05 g
e. If the actual yield of silver was 14.1 g, what is the percent yield of the
reaction?
Percent yield = Actual Yield / Theoretical yield * 100%
Percent yield = 11.05 / 14.1 * 100 = 78.36%