Question

Someone help me plz!!!
It’s algebra

Answer 1

Explanation:

c.

`a(x)=x^3-3\\b(x)=2x+1\\c(x)=(3)/(x+2) \\d(x)=4-x\\a.\\a(4)=4^3-3=64-3=61\\b.\\\\c(x-5)=(3)/(x-5+2) =(3)/(x-3) \\c.\\d(-1)=4-(-1)=4+1=5\\b(d(-1))=b(5)=2(5)+1=11\\\\d.\\(coa)(2)=c(a(2))=c(2^3-3)=c(8-3)=c(5)=(3)/(5+2) =(3)/(7)`