Answer:
![A=600\: u^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/1slm1yepmpcw0gi5l3m3fkduy1hkrce3g5.png)
The correct answer is letter c.
Explanation:
The area equation of a triangle is given by:
(1)
Where:
b is the base
h is the height
Let's find first the angle MJK (α), using the tangent definition.
![tan(\alpha)=(24)/(32)](https://img.qammunity.org/2022/formulas/mathematics/high-school/329etry00hp7f0wd4p3dlus9rsp1nou9o9.png)
![\alpha=tan^(-1)((24)/(32))](https://img.qammunity.org/2022/formulas/mathematics/high-school/gjk3l21ah2nbkxapbjfpl0skuuhvnhdmgh.png)
![\alpha=36.9^(\circ)](https://img.qammunity.org/2022/formulas/mathematics/high-school/di764w76pb4o4j193d0ub1zx0ln9hqvffw.png)
Now, if α = 37° then β (angle JLK) must be:
![37^(\circ) + \beta + 90^(\circ)=180^(\circ)](https://img.qammunity.org/2022/formulas/mathematics/high-school/uf1q9me9d25x8ut0bdvlsbn6v0c2rgoszf.png)
![\beta=53^(\circ)](https://img.qammunity.org/2022/formulas/mathematics/high-school/rqyys9ynyqfprnf1icsjo7xla8kntl1bwj.png)
Now, we can find the distance ML using again the tangent definition:
![tan(\beta)=(24)/(ML)](https://img.qammunity.org/2022/formulas/mathematics/high-school/l70x3d7uj6qlckqveiin3epw42bkl4i90p.png)
![ML=(24)/(tan(53))](https://img.qammunity.org/2022/formulas/mathematics/high-school/d8i0f8tdd22lmcwqnw84zvkkgtfc5kyh10.png)
![ML=18](https://img.qammunity.org/2022/formulas/mathematics/high-school/qkbxxl1pjcqji1ukw0h1m779ggtvksanyq.png)
The base of the triangle LKJ will be:
![b=32+ML=32+18=50](https://img.qammunity.org/2022/formulas/mathematics/high-school/j4yys75q8scq5kbrm80qaipg9zvhn0ufry.png)
Therefore, using equation (1) the area of △LKJ will be:
![A=(50*24)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/blnu4fm2cnr9ajugu4c9b4hdltqatimtuj.png)
![A=600\: u^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/1slm1yepmpcw0gi5l3m3fkduy1hkrce3g5.png)
The correct answer is c.
I hope it helps you!