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Put the equation y =x^2-8x + 12 into the form y(x-h)^2+k
Answer: y =

Put the equation y =x^2-8x + 12 into the form y(x-h)^2+k Answer: y =-example-1

2 Answers

6 votes

Answer:

y = (x - 4)² - 4

Explanation:

y = x² - 8x + 12

y = ( x² - 2(4)x + 4² ) - 4² + 12

y = (x - 4)² - 4

User Anirudh Jadhav
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The square for y = x^2 - 8x + 12, add (8/2)^2 = 16 to both sides, resulting in y = (x - 4)^2 + 12.

To put the equation y = x^2 - 8x + 12 into the form y = (x - h)^2 + k, we can complete the square.

First, we move the constant term to the left side of the equation:

y - 12 = x^2 - 8x

Next, we can factor the quadratic on the right side of the equation:

y - 12 = (x - 4)^2

Finally, we add 16 to both sides of the equation to isolate y on the left:

y = (x - 4)^2 + 12

Therefore, the equation y = x^2 - 8x + 12 can be written in the form y = (x - h)^2 + k as follows:

y = (x - 4)^2 + 12

where h = 4 and k = 12.

The image shows the equation y = x^2 - 8x + 12 in the form y = (x - h)^2 + k, where h = 4 and k = 12. The graph of the equation is a parabola with vertex at (4, 12).

User Ben Harold
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