156k views
5 votes
The combined area of a square and a rectangle is 33 square meters. The width of the rectangle is 1 meter more than the length of one side of the square and the length of the rectangle is 3 meters more

than its width.
a) Calculate the dimensions of the rectangle and its perimeter

b) Calculate the dimensions of the square.

1 Answer

5 votes

Answer:

4 m = width of the rectangle.

6 m = length of the rectangle

20 m = perimeter of rectangle

3 m = side of the square

Explanation:

Let s = length of side of square

s + 1 = width of rectangle

s + 3 = length of rectangle

Area of rectangle = (s + 1)(s + 3)

Area of square =
s^(2)

So, (s + 1)(s + 3) +
s^(2) = 33


s^(2) + 4s + 3 +
s^(2) = 33

2
s^(2) + 4s - 30 = 0

2(
s^(2) + 2s - 15) = 0

2(s + 5)(s - 3) = 0

s = -5 or s = 3

Length of a side cannot be negative, so -5 is ignored

3 m = side of the square

4 m = width of the rectangle

6 m = length of the rectangle

2(4) + 2(6) = 8 + 12 = 20 m = perimeter of rectangle

User Simon Doppler
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories