Answer:
The committee can be selected in 1,183,000 ways to contain equal numbers of men and women.
Explanation:
The order in which the people are chosen is not important, which means that the combinations formula is used to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_(n,x) = (n!)/(x!(n-x)!)](https://img.qammunity.org/2022/formulas/mathematics/college/mztppiaohythui2rvvokdfm636pzgsn6x6.png)
In how many ways could a 6 person committee be selected to contain equal numbers of men and women.
3 men from a set of 26
3 women from a set of 15. So
![T = C_(26,3)*C_(15,3) = (26!)/(3!23!)*(15!)/(3!12!) = 2600*455 = 1183000](https://img.qammunity.org/2022/formulas/mathematics/college/suw81g0wayut8nvdyopt5k2ol4uit392v5.png)
The committee can be selected in 1,183,000 ways to contain equal numbers of men and women.