1 Answer

Almedina · Answer 1 · 2022-05-07T23:08:24+0000

Given:

In triangle DEF,
DE = EF and
$m\angle 98^\circ$ .

To find:

The measure of angle EFD.

Solution:

In triangle DEF,

DE = EF (Given)

It means triangle DEF is an isosceles triangle.

$m\angle EDF=m\angle EFD$ (Base angles of an isosceles triangle are equal)

Using angle sum property in triangle DEF, we get

$m\angle DE F+m\angle EFD+m\angle EDF=180^\circ$

$98^\circ +m\angle EFD+m\angle EFD=180^\circ$

$2m\angle EFD=180^\circ-98^\circ$

$2m\angle EFD=82^\circ$

Divide both sides by 2.

$m\angle EFD=(82^\circ)/(2)$

$m\angle EFD=41^\circ$

Therefore, the measure of angle EFD is 41 degrees.

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