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Inverse trigonometric ratios


Inverse trigonometric ratios ​-example-1

1 Answer

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Answer:

Explanation:

  1. First we go to find the length of ZX
  2. Notice that the angle of 25 degrees is opposite of the side length of 15 and ZX is what were trying to find.
  3. Set up the equation sin25=15/x
  4. Now move the 15 to the other side, x*sin25=15
  5. now use your calculator to find x=35.4930238935
  6. now find angle x( the triangle on the right)
  7. notice that we the the side opposite to as 22 and the adjcent as 35.4930238935,we can use the tangent function to find the angle
  8. set up the equation tanx=22/35.4930238935
  9. tanx=0.619840114666
  10. x=tan^-1(0.619840114666)
  11. x=51.69554°
  12. now know that a triangle has a total of 180 degrees, now we have the two angles we can make a equation for W to find the angle
  13. W+51.69554+90=180
  14. W+51.69554=90
  15. W=38.30446

So the final Answer is m of W = 38.30446 degrees.

User Rishikarri
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