Question

2NaN3 produces 2Na+3N2 How many moles of each product are produced when 6 moles of NaN3 react?

Answer 1

`6molNa\\\\9molN_2`

Step-by-step explanation:

Hello there!

In this case, given the chemical reaction:

`2NaN_3\rightarrow 2Na+3N2`

It is possible to evidence the 2:2 mole ratio of the reactant to Na and the 2:3 mole ratio of the reactant to the N2; therefore, the following setups allows us to compute the moles of products:

`6molNaN_3*(2molNa)/(2molNaN_3)=6molNa\\\\6molNaN_3*(3molN_2)/(2molNaN_3)=9molN_2`

Best regards!