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Find the equation of the straight line which passes through the point (-1,3) and make intercept on x - axis as thrice that on y - axis .​

User Amnesia
by
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1 Answer

5 votes

Answer:


y = -(1)/(3)x + (8)/(3)

Explanation:

Given


(x_1,y_1) = (-1,3)


Intercept\ on\ x-axis = Intercept\ on\ y-axis.

Required

Determine the equation

First, we calculate the intercepts using:


(x)/(a) + (y)/(b) = 1

Where

b = Intercept on y axis.

a = Intercept on x axis.

From the question:


a = 3b

The equation becomes:


(x)/(3b) + (y)/(b) = 1

Multiply through by 3b


x + 3y = 3b

We have:
(x_1,y_1) = (-1,3)

So:


-1 + 3 * 3 = 3b


8 = 3b

Make b the subject


b = (8)/(3)

Substitute
b = (8)/(3) in
x + 3y = 3b to get the equation


x + 3y = 3 * (8)/(3)


x + 3y = 8

Make 3y the subject


3y = -x + 8

Make y the subject


y = -(1)/(3)x + (8)/(3)

User AndrewJM
by
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