Answer:
191.4 grams of cinnabar are required to obtain 165 grams of mercury.
Step-by-step explanation:
The balanced reaction is:
HgS + O₂ ⇒ Hg + SO₂
By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:
- HgS: 1 mole
- O₂: 1 mole
- Hg: 1 mole
- SO₂: 1 mole
Being the molar mass of each compound:
- HgS: 232g/mole
- O₂: 32 g/mole
- Hg: 200 g/mole
- SO₂: 64 g/mole
the following mass amounts of each compound participate in the reaction:
- HgS: 1 mole* 232 g/mole= 232 g
- O₂: 1 mole* 32 g/mole= 32 g
- Hg: 1 mole* 200 g/mole= 200 g
- SO₂: 1 mole* 64 g/mole= 64 g
Then you can apply the following rule of three: if by stoichiometry 200 grams of Hg are formed from 232 grams of HgS , 165 grams of Hg are formed from how many grams of HgS?
mass of HgS= 191.4 grams
191.4 grams of cinnabar are required to obtain 165 grams of mercury.