Question

You are working as an electrical technician. One day, out in CR the field, you need an inductor but cannot find one. Look- ing in your wire supply cabinet, you find a cardboard tube with single-conductor wire wrapped uniformly around it to form a solenoid. You carefully count the turns of wire and find that there are 580 turns. The diameter of the tube is 8.00 cm, and the length of the wire-wrapped portion is 36.0 cm. You pull out your calculator to determine (a) the inductance of the coil and (b) the emf generated in it if the current in the wire increases at the rate of 4.00 A/s.

Answer 1

a. 5.901x10⁻³H

b. 2.36x10⁻²V

Step-by-step explanation:

a. inductance of coil

we calculate the inductance of coil using this formula

L = N²μπA/λ

= [N²μπd²/4]/λ

we substitute values

L = 580² x 4πx10⁻⁷ x π(8x10⁻²)²/ 4x0.36

L = 336400 x 0.000001257 x 0,020096/1.44

L = 0.005901

= 5.901x10⁻³H

b. EMF

|e| = Ldi/dt

= 0.005901 * 4.00

= 0.023604

= 2.36x10⁻²V