Question

A sealed, empty 1.0 L plastic sports bottle is sitting on a porch

in the hot sunlight. The temperature of the air inside the bottle
is 39 °C (312 K). When the sun goes down, the air in the bottle
cools to 20.°C (293 K). Assuming that the bottle is completely
flexible, what is the volume of air at the cooler temperature?

Answer 1

Using Charles' Law, we can determine that the volume of air at the cooler temperature of 20°C is approximately 0.935 L.

Step-by-step explanation:

To find the volume of air at the cooler temperature, we can use Charles' Law, which states that the volume of a gas is directly proportional to its temperature, as long as the pressure is constant.

We can set up the equation:

V1/T1 = V2/T2

Where:

V1 = initial volume of air = 1.0 L

T1 = initial temperature in Kelvin = 312 K

V2 = final volume of air (which is what we're trying to find)

T2 = final temperature in Kelvin = 293 K

Plugging in the values, we get:

1.0 L / 312 K = V2 / 293 K

Cross multiplying, we find:

V2 = (1.0 L * 293 K) / 312 K

Simplifying, the volume of air at the cooler temperature is approximately 0.935 L.

Answer 2

The answer is flexing 20 centimeters and 30 meters