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15 votes
Find the axis of symmetry of the parabola. Y=2x^2+4x-1

User Highpost
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2 Answers

17 votes
17 votes

Answer:

The axis of symmetry is the line x=1, , and the vertex is the point (1, -1).

Explanation:

The standard form of a quadratic function is y= ax^2 + bx + c The formula for finding the equation of the axis of symmetry is x= -b/2a The x-coordinate of the vertex is also -b/2a and the y-coordinate of the vertex is given by substituting the x-coordinate of the vertex into the original function.

For y= 2x^2 - 4x +1, a= 2,b= -4, and c=1

The axis of symmetry is:

x= -1 ⋅ -4/ 2⋅2

x=4/4

x=1

The x-coordinate of the vertex is also 1. The y-coordinate of the vertex is found by:

y= 2(1)^2 -4(1)+1

y=2(1) -4+1

y=2-3

y= -1

So, the vertex is the point (1, -1).

Hope this helps please let me know if I'm wrong.

User Guforu
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2.5k points
12 votes
12 votes

Answer:

x = - 1

Explanation:

Find the axis of symmetry of the parabola. Y=2x^2+4x-1-example-1