Question

A 4kg watermelon is dropped from a height of 45m. What is the velocity of the watermelon just before it hits the ground?

Answer 1

v=30 m/s

Step-by-step explanation:

h - height

g - acceleration due to gravity=10

t - time

v- velocity

`h = (1)/(2) * g * t {}^(2)`

45 = 5t²

t² = 9

t=3 seconds

v=g×t

v=10×3

v=30 m/s