132k views
10 votes
Find the axis of symmetry of the parabola. Y=2x^2+4x-1

2 Answers

8 votes

Answer:

The axis of symmetry is the line x=1, , and the vertex is the point (1, -1).

Explanation:

The standard form of a quadratic function is y= ax^2 + bx + c The formula for finding the equation of the axis of symmetry is x= -b/2a The x-coordinate of the vertex is also -b/2a and the y-coordinate of the vertex is given by substituting the x-coordinate of the vertex into the original function.

For y= 2x^2 - 4x +1, a= 2,b= -4, and c=1

The axis of symmetry is:

x= -1 ⋅ -4/ 2⋅2

x=4/4

x=1

The x-coordinate of the vertex is also 1. The y-coordinate of the vertex is found by:

y= 2(1)^2 -4(1)+1

y=2(1) -4+1

y=2-3

y= -1

So, the vertex is the point (1, -1).

Hope this helps please let me know if I'm wrong.

User Mikeysee
by
7.8k points
5 votes

Answer:

x = - 1

Explanation:

Find the axis of symmetry of the parabola. Y=2x^2+4x-1-example-1
User Mikhaela
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories