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If f(x)=−x2−8x+7 and g(x)=x−1, what does (g−f)(x) equal? A)(g−f)(x)=−x2−9x+8 B)(g−f)(x)=−x2−7x+6 C)(g−f)(x)=−8x+8 D)(g−f)(x)=x2+9x−8

If f(x)=−x2−8x+7 and g(x)=x−1, what does (g−f)(x) equal? A)(g−f)(x)=−x2−9x+8 B)(g−f)(x)=−x2−7x+6 C)(g−f)(x)=−8x+8 D)(g−f)(x)=x2+9x−8
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If f(x)=−x2−8x+7 and g(x)=x−1, what does (g−f)(x) equal?

A)(g−f)(x)=−x2−9x+8
B)(g−f)(x)=−x2−7x+6
C)(g−f)(x)=−8x+8
D)(g−f)(x)=x2+9x−8

User Rrehbein
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1 Answer

6 votes
Answer is D we just have to subtract f(x) from g(x)
User Snow
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