√(x - 1) (x - 6) {}^(2) inflection points?​

Question

`√(x - 1) (x - 6) {}^(2)`
inflection points?​

Answer 1

1 and 6

Explanation:

it is just like the roots of a polynomial, since
`√(x-1)`(x-6)^2=0

we can separate the two pieces of the problem

\sqrt{x-1} =0

square both sides to get

x-1=0. x=1

(x-6)^2=0

square root both sides and get

x-6=0

x=6

so the two inflection points of the equation are 6 and 1

Hope that helps :)