Question

Start at 4 3/4 and count on steps of 1/4. If 4 3/4 is the first number in the sequence write down the 3rd number and the 6th number and the 9th number

Answer 1

5 1/4 ; 6 ; 6 3/4

Explanation:

Using the nth term of an arithmetic progression relation.

an = a + (n - 1)d

First term, a = 4 3/4

Common difference, d = 1/4

3 rd term ; n = 3

a3 = 4 3/4 + (3 - 1)1/4

a3 = 4 3/4 + 2*1/4

a3 = 4 3/4 + 1/2

a3 = 5 1/4

6th term ; n = 6

a6 = 4 3/4 + (6 - 1)1/4

a6 = 4 3/4 + 5*1/4

a6 = 4 3/4 + 5/4

a6 = 6

9 th term ; n = 3

a9 = 4 3/4 + (9 - 1)1/4

a9 = 4 3/4 + 8*1/4

a9 = 4 3/4 + 2

a9 = 6 3/4