18.2k views
3 votes
If one tenement on the Lower East Side of New York had 101 adults and 91 children, and there was an average of 8 persons in a tenement apartment, how many apartments did this tenement have?

1 Answer

2 votes

Answer:

24 Apartments

Explanation:

To get the total amount of people living in the apartment building, you add 101 and 92.

101+91=192 total people

You then divide this total by the amount of people staying in each apartment, which is 8.

192/8=24 apartments

This leaves you with 24 apartments, with 8 people living in each one.

User Omegalen
by
7.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.