Question

When cobalt(II) chloride is allowed to react with sodium hydroxide, the resulting

products are cobalt(II) hydroxide and sodium chloride. Determine the mass of
cobalt(II) chloride required to completely react with 114g of sodium hydroxide.

Answer 1

To completely react with 114g of sodium hydroxide, 184.77g of cobalt(II) chloride is required.

Step-by-step explanation:

To determine the mass of cobalt(II) chloride required to completely react with 114g of sodium hydroxide, we need to first write the balanced equation for the reaction:

CoCl2(aq) + 2NaOH(aq) → Co(OH)2(s) + 2NaCl(aq)

From the equation, we can see that the stoichiometric ratio of CoCl2 to NaOH is 1:2. This means that one mole of CoCl2 reacts with two moles of NaOH. We can use the molar mass of NaOH to calculate the moles of NaOH in 114g:

114g NaOH x (1 mol NaOH/40g NaOH) = 2.85 mol NaOH

Since the stoichiometric ratio is 1:2, we will need half as many moles of CoCl2 to completely react with the given amount of NaOH. So, the mass of CoCl2 required is:

2.85 mol NaOH x (1 mol CoCl2/2 mol NaOH) x (129g CoCl2/mol CoCl2) = 184.77g CoCl2

Answer 2

Reaction CoCl2 + 2 NaOH -> Co(OH)2 + 2 NaOH

You need to count number of moles of NaOH

Amount of mole is n = m/M = 114 g / 39.998 g/mol = 28,5 mol (about)

Amount of CoCl2 is half from that

Calculate molar mass of CoCl2 and multiply it by 28,5 mol

Step-by-step explanation: