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1 vote
Part A

Steve buys 2 lb of grapefruit and 3 lb of oranges for $7.20. Kennedy buys 4 lb of grapefruit and 2 lb of oranges for $8.80. Let x represent the price
per pound for grapefruit, and let y represent the price per pound for oranges. Choose the system of equations that models the situation.
A. 2x + 3y = 7.20
2x + 4y = 8.80
B. 3x +2y = 7.20
4x + 2y = 8.80
C. 2x + 3y = 7.20
4x + 2y = 8.80
D. 2x + 3y = 8.80
4x + 2y = 7.20
Part B
Steve buys 2 lb of grapefruit and 3 lb of oranges for $7.20. Kennedy buys 4 lb of grapefruit and 2 lb of oranges for $8.80. Let x represent the price
per pound for grapefruit, and let y represent the price per pound for oranges. Use the system of equations from Part A to find the price per pound
for oranges
price: $
per pound

1 Answer

2 votes
The answer is, C
2x +3y=7.20
4x+2y=8.80
User FernandoEscher
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