Question

How many moles of oxygen gas are produced from the decomposition of six moles of potassium

chloride? 2KCIO3 --> 2KCI+ 3O2
A: 9 mol
B: 3 mol
C: 6 mol

Answer 1

A: 9 mol

Step-by-step explanation:

The reaction is

`2KClO_3\rightarrow 2KCl+3O_2`

The stoichiometric relation is given by

`\text{Number of moles of }KClO_3* \frac{\text{Moles of}\ O_2}{\text{Moles of}\ KClO_3}\\ =\text{6 mol of}\ KClO_3* \frac{\text{3 mol of }O_2}{\text{2 mol of }KClO_3}\\ =9\ \text{mol of }O_2`

The moles of oxygen gas produced in the given reaction is
`9\ \text{mol of }O_2`.