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Assume the data link protocol used by NDAS has the following associated characteristics:

An 8-bit ASCII code is used. Each frame has a size (length) of 11936 bits. A half-duplex circuit with a speed of 1 million bits per second is used for transmission. There is a 30-millisecond turnaround time on the half-duplex circuit. Each frame contains 20 overhead (non-user-data) bytes. Assume that the probability of a frame requiring retransmission due to error in transmission is 1 percent. A millisecond is one-thousandth of a second. Also, 8 bits = 1 character = 1byte

Fill in the blanks

K= _________ bits per bytes
M=_________ bytes
C= _________ overhead bytes

User Kiwiron
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Answer:

The transmission speed = 0.278 MB/s

Step-by-step explanation:

K = 8 bits

M = 11936/8 bits = 1492 bits

transmission rate R = 1000000/ 8 = 125000 bps

overhead bytes C = 20

probability = 0.01

time T = 30 ms = 30 x10^-3 s

The data transmission speed formula = K(M-C)(1-p) / (M/R) + T

= 8( 1492 - 20)(0.99)/ (1492/125000) + 30 x10^-3

= 0.278 MB/s

User Jc John
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