Question

B(1)= -12

b(n)=b(n−1)⋅4

Find the 3rd term of the sequence. Show me the solutions and calculations.​

Answer 1

Given:

`b(1)=-12`

`b(n)=b(n-1)\cdot 4`

To find:

The third term of the sequence.

Solution:

We have,

`b(n)=b(n-1)\cdot 4`

For n=2, we get

`b(2)=b(2-1)\cdot 4`

`b(2)=b(1)\cdot 4`

`b(2)=-12\cdot 4`
`[\because b(1)=-12]`

`b(2)=-48`

For n=3, we get

`b(3)=b(3-1)\cdot 4`

`b(3)=b(2)\cdot 4`

`b(3)=-48\cdot 4`
`[\because b(2)=-48]`

`b(3)=-192`

Therefore, the 3rd term of the sequence is -192.