Answer:
the fundamental frequency produced by the open pipe is 120.78 Hz
Step-by-step explanation:
Given;
length of the open pipe, L = 1.42 m
speed of sound in air, v = 343 m/s
The length of the open pipe for the fundamental frequency is equivalent to half of wavelength;
![L = (\lambda)/(2) \\\\\lambda = 2L](https://img.qammunity.org/2022/formulas/physics/college/ju8hxvf1m4tag0tvmmw269zlv1qafyb5wi.png)
The fundamental frequency produced by the open pipe is calculated as;
![f_o = (v)/(\lambda) \\\\f_o = (v)/(2L) \\\\f_o = (343)/(2 * 1.42) \\\\f_o = 120.78 \ Hz](https://img.qammunity.org/2022/formulas/physics/college/f153emh390f0a194br123rdnlooitf3c89.png)
Therefore, the fundamental frequency produced by the open pipe is 120.78 Hz