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Let y = x² In(x).
dy/dx the lesson is differentiate products​

User Olefrank
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1 Answer

3 votes

Answer:

dy/dx = x(1+2lnx)

Explanation:

Given y = x² In(x).

dy/dx = Udv/dx + Vdu/dx

Let U = x², V = lnx

du/dx = 2x

dv/dx = 1/x

Substitute into the formula;

dy/dx = x²(1/x) + lnx(2x)

dy/dx = x + 2xlnx

dy/dx = x(1+2lnx)

User Rezo Megrelidze
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